What is the solution for (dy}{dx}y=\frac{x^3)/3-x ?

The solution for (dy}{dx}y=\frac{x^3)/3-x is y=sqrt((x^4)/6-x^2+c_{1)},y=-sqrt((x^4)/6-x^2+c_{1)}

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(dy}{dx}y=\frac{x^3)/3-x

\frac{d y}{d x} y = \frac{x ^{3}}{3} - x

y = \frac{x ^{4}}{6} - x^{2} + c_{1}, y = - \frac{x ^{4}}{6} - x^{2} + c_{1}

Solution steps

\frac{d y}{d x} y = \frac{x ^{3}}{3} - x

Solve separable ODE:

y = \frac{x ^{4}}{6} - x^{2} + c_{1}, y = - \frac{x ^{4}}{6} - x^{2} + c_{1}

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What is the solution for (dy}{dx}y=\frac{x^3)/3-x ?
The solution for (dy}{dx}y=\frac{x^3)/3-x is y=sqrt((x^4)/6-x^2+c_{1)},y=-sqrt((x^4)/6-x^2+c_{1)}