What is the integral from 2 to 3 of 1/(sqrt(x-3)) ?

The integral from 2 to 3 of 1/(sqrt(x-3)) is -2i

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integral from 2 to 3 of 1/(sqrt(x-3))

\int_{2}^{3} \frac{1}{x - 3} d x

- 2 i

Solution steps

\int_{2}^{3} \frac{1}{x - 3} d x

Apply u-substitution

: \int_{i}^{0} 2 d u

= \int_{i}^{0} 2 d u

Integral of a constant:

\int a d x = a x

= [2 u]_{i}^{0}

Compute the boundaries:

- 2 i

= - 2 i

y = 3 x^{2} - 4

\int 1 + cos (4 x) d x

5 x^{3} + 4 x

\int_{0}^{\infty} \frac{1}{x ^{2} + x} d x

\frac{\partial}{\partial y} (\frac{1}{x ^{2} + y ^{2} + 1})

What is the integral from 2 to 3 of 1/(sqrt(x-3)) ?
The integral from 2 to 3 of 1/(sqrt(x-3)) is -2i