What is (\partial)/(\partial x)(yz^2cos(x)) ?

The answer to (\partial)/(\partial x)(yz^2cos(x)) is -yz^2sin(x)

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(\partial)/(\partial x)(yz^2cos(x))

\frac{\partial}{\partial x} (y z^{2} cos (x))

- y z^{2} sin (x)

Solution steps

\frac{\partial}{\partial x} (y z^{2} cos (x))

Treat

y, z

as constants

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= y z^{2} \frac{\partial}{\partial x} (cos (x))

Apply the common derivative:

\frac{\partial}{\partial x} (cos (x)) = - sin (x)

= y z^{2} (- sin (x))

Simplify

= - y z^{2} sin (x)

\int_{- 8}^{8} \frac{( 64 - x ^{2} )}{2} d x

\int \frac{3}{x ^{5}} d x

\frac{\partial}{\partial x} (x^{4} \cdot y^{2} - x^{3} \cdot y)

f (x) = e^{2 x + 1}

\frac{d}{d x} (x^{3} + a x^{2} y + b x y^{2} + y^{3})

What is (\partial)/(\partial x)(yz^2cos(x)) ?
The answer to (\partial)/(\partial x)(yz^2cos(x)) is -yz^2sin(x)