What is (\partial)/(\partial x)((xe^y)/(x+y)) ?

The answer to (\partial)/(\partial x)((xe^y)/(x+y)) is (e^yy)/((x+y)^2)

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(\partial)/(\partial x)((xe^y)/(x+y))

\frac{\partial}{\partial x} (\frac{x e ^{y}}{x + y})

\frac{e ^{y} y}{( x + y ) ^{2}}

Solution steps

\frac{\partial}{\partial x} (\frac{x e ^{y}}{x + y})

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= e^{y} \frac{\partial}{\partial x} (\frac{x}{x + y})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= e^{y} \frac{\frac{\partial}{\partial x} ( x ) ( x + y ) - \frac{\partial}{\partial x} ( x + y ) x}{( x + y ) ^{2}}

\frac{\partial}{\partial x} (x) = 1

\frac{\partial}{\partial x} (x + y) = 1

= e^{y} \frac{1 \cdot ( x + y ) - 1 \cdot x}{( x + y ) ^{2}}

Simplify

e^{y} \frac{1 \cdot ( x + y ) - 1 \cdot x}{( x + y ) ^{2}} : \frac{e ^{y} y}{( x + y ) ^{2}}

= \frac{e ^{y} y}{( x + y ) ^{2}}

x \to 1 lim (2^{\frac{1}{x - 1}})

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What is (\partial)/(\partial x)((xe^y)/(x+y)) ?
The answer to (\partial)/(\partial x)((xe^y)/(x+y)) is (e^yy)/((x+y)^2)