What is (\partial)/(\partial v)(1/4 (u-v)) ?

The answer to (\partial)/(\partial v)(1/4 (u-v)) is -1/4

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(\partial)/(\partial v)(1/4 (u-v))

\frac{\partial}{\partial v} (\frac{1}{4} (u - v))

- \frac{1}{4}

Solution steps

\frac{\partial}{\partial v} (\frac{1}{4} (u - v))

Treat

u

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{1}{4} \frac{\partial}{\partial v} (u - v)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{1}{4} (\frac{\partial}{\partial v} (u) - \frac{\partial}{\partial v} (v))

\frac{\partial}{\partial v} (u) = 0

\frac{\partial}{\partial v} (v) = 1

= \frac{1}{4} (0 - 1)

Simplify

= - \frac{1}{4}

f (x) = (x - 1)^{2}

n = 1 \sum \infty e^{\frac{1}{n}}

x \to 0 lim (1 + x)

y = 8 x^{\frac{1}{2}} + 8 x^{\frac{3}{2}} + 6, at x = 4

\int \frac{2 + x}{2 - x} d x

What is (\partial)/(\partial v)(1/4 (u-v)) ?
The answer to (\partial)/(\partial v)(1/4 (u-v)) is -1/4