What is the tangent of f(x)=4tan(x),\at x= pi/6 ?

The tangent of f(x)=4tan(x),\at x= pi/6 is y= 16/3 x+4/(sqrt(3))-(8pi)/9

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tangent of f(x)=4tan(x),\at x= pi/6

tangent of

f (x) = 4 tan (x), at x = \frac{π}{6}

y = \frac{16}{3} x + \frac{4}{3} - \frac{8 π}{9}

Solution steps

Find the tangent point:

(\frac{π}{6}, \frac{4}{3})

Find the slope of

f (x) = 4 tan (x) : \frac{df ( x )}{d x} = 4 sec^{2} (x)

Compute the slope of

f (x) = 4 tan (x)

x = \frac{π}{6} : m = \frac{16}{3}

Find the line with slope m=

\frac{16}{3}

and passing through

(\frac{π}{6}, \frac{4}{3}) : y = \frac{16}{3} x + \frac{4}{3} - \frac{8 π}{9}

y = \frac{16}{3} x + \frac{4}{3} - \frac{8 π}{9}

\frac{d}{d x} (ln (x^{3}) + 2 x)

\frac{d}{d x} (cos (x) sin^{2} (x))

y^{^{'}} = - 4 x y

\frac{\partial}{\partial x} (\frac{x y}{x + 7})

\int arcsec (x) d x

What is the tangent of f(x)=4tan(x),\at x= pi/6 ?
The tangent of f(x)=4tan(x),\at x= pi/6 is y= 16/3 x+4/(sqrt(3))-(8pi)/9