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Popular >

x^'+x+2=0

Solution

x^{^{'}} + x + 2 = 0

Solution

x = e^{- t - c_{1}} - 2

Solution steps

x^{'} (t) + x + 2 = 0

Solve separable ODE:

x = e^{- t - c_{1}} - 2

x = e^{- t - c_{1}} - 2

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Frequently Asked Questions (FAQ)

What is the solution for x^'+x+2=0 ?
The solution for x^'+x+2=0 is x=e^{-t-c_{1}}-2