What is the derivative of Acos(x+Bsin(x)) ?

The derivative of Acos(x+Bsin(x)) is -Asin(x)+Bcos(x)

What is the first derivative of Acos(x+Bsin(x)) ?

The first derivative of Acos(x+Bsin(x)) is -Asin(x)+Bcos(x)

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\frac{d}{d x} (A cos (x) + B sin (x))

- A sin (x) + B cos (x)

Solution steps

\frac{d}{d x} (A cos (x) + B sin (x))

Treat

A, B

as constants

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (A cos (x)) + \frac{d}{d x} (B sin (x))

\frac{d}{d x} (A cos (x)) = - A sin (x)

\frac{d}{d x} (B sin (x)) = B cos (x)

= - A sin (x) + B cos (x)

\frac{d}{d x} (- \frac{2}{9 x ^{\frac{4}{3}}})

\int_{- 1}^{6} - x^{2} + 5 x + 6 d x

x \to 0 + lim (\frac{∣ 8 x ∣}{x})

y = sin^{2} (π x), [0, 1]

\frac{d}{d x} (\frac{5}{x + 4})

What is the derivative of Acos(x+Bsin(x)) ?
The derivative of Acos(x+Bsin(x)) is -Asin(x)+Bcos(x)
What is the first derivative of Acos(x+Bsin(x)) ?
The first derivative of Acos(x+Bsin(x)) is -Asin(x)+Bcos(x)