What is the derivative of-2/(9x^{4/3}) ?

The derivative of-2/(9x^{4/3}) is 8/(27x^{7/3)}

What is the first derivative of-2/(9x^{4/3}) ?

The first derivative of-2/(9x^{4/3}) is 8/(27x^{7/3)}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

\frac{d}{d x} (- \frac{2}{9 x ^{\frac{4}{3}}})

\frac{8}{27 x ^{\frac{7}{3}}}

Solution steps

\frac{d}{d x} (- \frac{2}{9 x ^{\frac{4}{3}}})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - \frac{2}{9} \frac{d}{d x} (\frac{1}{x ^{\frac{4}{3}}})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= - \frac{2}{9} \frac{d}{d x} (x^{- \frac{4}{3}})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= - \frac{2}{9} (- \frac{4}{3} x^{- \frac{4}{3} - 1})

Simplify

- \frac{2}{9} (- \frac{4}{3} x^{- \frac{4}{3} - 1}) : \frac{8}{27 x ^{\frac{7}{3}}}

= \frac{8}{27 x ^{\frac{7}{3}}}

\int_{- 1}^{6} - x^{2} + 5 x + 6 d x

x \to 0 + lim (\frac{∣ 8 x ∣}{x})

y = sin^{2} (π x), [0, 1]

\frac{d}{d x} (\frac{5}{x + 4})

\frac{d ^{2}}{d x ^{2}} (\frac{x ^{2}}{9 + 8 x})

What is the derivative of-2/(9x^{4/3}) ?
The derivative of-2/(9x^{4/3}) is 8/(27x^{7/3)}
What is the first derivative of-2/(9x^{4/3}) ?
The first derivative of-2/(9x^{4/3}) is 8/(27x^{7/3)}