What is the integral from-1 to 6 of-x^2+5x+6 ?

The integral from-1 to 6 of-x^2+5x+6 is 343/6

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integral from-1 to 6 of-x^2+5x+6

\int_{- 1}^{6} - x^{2} + 5 x + 6 d x

\frac{343}{6}

Decimal Notation

57.16666 \dots

Solution steps

\int_{- 1}^{6} - x^{2} + 5 x + 6 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= - \int_{- 1}^{6} x^{2} d x + \int_{- 1}^{6} 5 x d x + \int_{- 1}^{6} 6 d x

\int_{- 1}^{6} x^{2} d x = \frac{217}{3}

\int_{- 1}^{6} 5 x d x = \frac{175}{2}

\int_{- 1}^{6} 6 d x = 42

= - \frac{217}{3} + \frac{175}{2} + 42

Simplify

- \frac{217}{3} + \frac{175}{2} + 42 : \frac{343}{6}

= \frac{343}{6}

x \to 0 + lim (\frac{∣ 8 x ∣}{x})

y = sin^{2} (π x), [0, 1]

\frac{d}{d x} (\frac{5}{x + 4})

\frac{d ^{2}}{d x ^{2}} (\frac{x ^{2}}{9 + 8 x})

\int_{0}^{2} - 2 x^{2} - 4 d x

What is the integral from-1 to 6 of-x^2+5x+6 ?
The integral from-1 to 6 of-x^2+5x+6 is 343/6