What is area y=3+2sqrt(x),y=(6+x)/2 ?

The answer to area y=3+2sqrt(x),y=(6+x)/2 is 64/3

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area y=3+2sqrt(x),y=(6+x)/2

area

y = 3 + 2 x, y = \frac{6 + x}{2}

\frac{64}{3}

Decimal Notation

21.33333 \dots

Solution steps

Apply the area formula:

\int_{0}^{16} 3 + 2 x - \frac{6 + x}{2} d x

Solve

\int_{0}^{16} 3 + 2 x - \frac{6 + x}{2} d x : \frac{64}{3}

The area is:

= \frac{64}{3}

x \to - 1 lim (x^{2} + 8 x + 8)

\int \frac{37}{37 + e ^{x}} d x

x y^{^{'}} + y - y^{2} e^{2 x} = 0

f (x) = 7 ln (x)

\frac{d y}{d x} + y cos (x) = 7 cos (x), y (0) = 9

What is area y=3+2sqrt(x),y=(6+x)/2 ?
The answer to area y=3+2sqrt(x),y=(6+x)/2 is 64/3