What is the solution for xy^'+y-y^2e^{2x}=0 ?

The solution for xy^'+y-y^2e^{2x}=0 is y= 1/(e^{2x)-2x\Ei(2x)+c_{1}x}

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xy^'+y-y^2e^{2x}=0

x y^{^{'}} + y - y^{2} e^{2 x} = 0

y = \frac{1}{e ^{2 x} - 2 x Ei ( 2 x ) + c _{1} x}

Solution steps

x y^{'} (x) + y - y^{2} e^{2 x} = 0

Solve Bernoulli ODE:

y = \frac{1}{e ^{2 x} - 2 x Ei ( 2 x ) + c _{1} x}

y = \frac{1}{e ^{2 x} - 2 x Ei ( 2 x ) + c _{1} x}

f (x) = 7 ln (x)

\frac{d y}{d x} + y cos (x) = 7 cos (x), y (0) = 9

2 x^{2} - 5 x - 3

\int_{- 3}^{x} (t + 3) d t

\int \frac{cos ( x )}{sin ^{5} ( x )} d x

What is the solution for xy^'+y-y^2e^{2x}=0 ?
The solution for xy^'+y-y^2e^{2x}=0 is y= 1/(e^{2x)-2x\Ei(2x)+c_{1}x}