What is the derivative of (-x^2-9)/((x^2-9)^2) ?

The derivative of (-x^2-9)/((x^2-9)^2) is -(2x(-x^2-27))/((x^2-9)^3)

What is the first derivative of (-x^2-9)/((x^2-9)^2) ?

The first derivative of (-x^2-9)/((x^2-9)^2) is -(2x(-x^2-27))/((x^2-9)^3)

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derivative of

\frac{- x ^{2} - 9}{( x ^{2} - 9 ) ^{2}}

- \frac{2 x ( - x ^{2} - 27 )}{( x ^{2} - 9 ) ^{3}}

Solution steps

\frac{d}{d x} (\frac{- x ^{2} - 9}{( x ^{2} - 9 ) ^{2}})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{d}{d x} ( - x ^{2} - 9 ) ( x ^{2} - 9 ) ^{2} - \frac{d}{d x} ( ( x ^{2} - 9 ) ^{2} ) ( - x ^{2} - 9 )}{( ( x ^{2} - 9 ) ^{2} ) ^{2}}

\frac{d}{d x} (- x^{2} - 9) = - 2 x

\frac{d}{d x} ((x^{2} - 9)^{2}) = 4 x (x^{2} - 9)

= \frac{( - 2 x ) ( x ^{2} - 9 ) ^{2} - 4 x ( x ^{2} - 9 ) ( - x ^{2} - 9 )}{( ( x ^{2} - 9 ) ^{2} ) ^{2}}

Simplify

\frac{( - 2 x ) ( x ^{2} - 9 ) ^{2} - 4 x ( x ^{2} - 9 ) ( - x ^{2} - 9 )}{( ( x ^{2} - 9 ) ^{2} ) ^{2}} : - \frac{2 x ( - x ^{2} - 27 )}{( x ^{2} - 9 ) ^{3}}

= - \frac{2 x ( - x ^{2} - 27 )}{( x ^{2} - 9 ) ^{3}}

y^{2} = 2 x - 2, y = x - 5

\frac{\partial}{\partial x} (cos (x^{2} y))

\int - 2 x + 18 x^{2} - 4 x^{3} + 18 d x

x \to 0 + lim (e^{- \frac{2}{x}})

What is the derivative of (-x^2-9)/((x^2-9)^2) ?
The derivative of (-x^2-9)/((x^2-9)^2) is -(2x(-x^2-27))/((x^2-9)^3)
What is the first derivative of (-x^2-9)/((x^2-9)^2) ?
The first derivative of (-x^2-9)/((x^2-9)^2) is -(2x(-x^2-27))/((x^2-9)^3)