What is the derivative of (2d/(x^3)-a) ?

The derivative of (2d/(x^3)-a) is -(6d)/(x^4)

What is the first derivative of (2d/(x^3)-a) ?

The first derivative of (2d/(x^3)-a) is -(6d)/(x^4)

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\frac{d}{d x} (\frac{2 d}{x ^{3}} - a)

- \frac{6 d}{x ^{4}}

Solution steps

\frac{d}{d x} (\frac{2 d}{x ^{3}} - a)

Treat

a, d

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (\frac{2 d}{x ^{3}}) - \frac{d a}{d x}

\frac{d}{d x} (\frac{2 d}{x ^{3}}) = - \frac{6 d}{x ^{4}}

\frac{d a}{d x} = 0

= - \frac{6 d}{x ^{4}} - 0

Simplify

= - \frac{6 d}{x ^{4}}

f (x) = \frac{10 x + x ^{2}}{( 5 + x ) ^{2}}

\frac{d y}{d x} - \frac{2 x ^{3}}{y} = 0

\int \frac{10}{9 - 16 x ^{2}} d x

\int \frac{1}{x ^{2} + 4 x - 12} d x

y^{^{''}} + 6 y^{^{'}} + 8 y = 0, y (0) = 9

What is the derivative of (2d/(x^3)-a) ?
The derivative of (2d/(x^3)-a) is -(6d)/(x^4)
What is the first derivative of (2d/(x^3)-a) ?
The first derivative of (2d/(x^3)-a) is -(6d)/(x^4)