What is (\partial)/(\partial x)(-3/(x^2)) ?

The answer to (\partial)/(\partial x)(-3/(x^2)) is 6/(x^3)

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(\partial)/(\partial x)(-3/(x^2))

\frac{\partial}{\partial x} (- \frac{3}{x ^{2}})

\frac{6}{x ^{3}}

Solution steps

\frac{\partial}{\partial x} (- \frac{3}{x ^{2}})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - 3 \frac{\partial}{\partial x} (\frac{1}{x ^{2}})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= - 3 \frac{\partial}{\partial x} (x^{- 2})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= - 3 (- 2 x^{- 2 - 1})

Simplify

- 3 (- 2 x^{- 2 - 1}) : \frac{6}{x ^{3}}

= \frac{6}{x ^{3}}

\frac{d y}{d x}, y = x^{- 10 c o s (x)}

f (x) = \frac{x ^{2} - 1}{x ^{2} + x + 1}, (1, 0)

(1 + x) \frac{d y}{d x} - x y = x + x^{2}

\frac{d}{d x} (x^{8 y})

y = arcsin (2 x), x = \frac{3}{4}

What is (\partial)/(\partial x)(-3/(x^2)) ?
The answer to (\partial)/(\partial x)(-3/(x^2)) is 6/(x^3)