What is area y=arcsin(2x),x=(sqrt(3))/4 ?

The answer to area y=arcsin(2x),x=(sqrt(3))/4 is (pi+sqrt(3))/(4sqrt(3))-1/2

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area y=arcsin(2x),x=(sqrt(3))/4

area

y = arcsin (2 x), x = \frac{3}{4}

\frac{π + 3}{4 3} - \frac{1}{2}

Decimal Notation

0.20344 \dots

Solution steps

Apply the area formula:

\int_{0}^{\frac{3}{4}} ∣ arcsin (2 x) ∣ d x

Solve

\int_{0}^{\frac{3}{4}} ∣ arcsin (2 x) ∣ d x : \frac{π + 3}{4 3} - \frac{1}{2}

The area is:

= \frac{π + 3}{4 3} - \frac{1}{2}

y^{^{'}} = (y + 5) (x + 2)

\int_{0}^{1} \frac{18}{4 y - 1} d y

f (x) = \frac{7}{x}, at x = 4

f (x) = ln (cos^{2} (x))

x \to 0 lim ((e^{x} + x)^{\frac{4}{x}})

What is area y=arcsin(2x),x=(sqrt(3))/4 ?
The answer to area y=arcsin(2x),x=(sqrt(3))/4 is (pi+sqrt(3))/(4sqrt(3))-1/2