What is the tangent of f(x)=(x^2-1)/(x^2+x+1),(1,0) ?

The tangent of f(x)=(x^2-1)/(x^2+x+1),(1,0) is y= 2/3 x-2/3

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tangent of f(x)=(x^2-1)/(x^2+x+1),(1,0)

tangent of

f (x) = \frac{x ^{2} - 1}{x ^{2} + x + 1}, (1, 0)

y = \frac{2}{3} x - \frac{2}{3}

Solution steps

Find the slope of

f (x) = \frac{x ^{2} - 1}{x ^{2} + x + 1} : \frac{df ( x )}{d x} = \frac{x ^{2} + 4 x + 1}{( x ^{2} + x + 1 ) ^{2}}

Compute the slope of

f (x) = \frac{x ^{2} - 1}{x ^{2} + x + 1}

(1, 0) : m = \frac{2}{3}

Find the line with slope m=

\frac{2}{3}

and passing through

(1, 0) : y = \frac{2}{3} x - \frac{2}{3}

y = \frac{2}{3} x - \frac{2}{3}

(1 + x) \frac{d y}{d x} - x y = x + x^{2}

\frac{d}{d x} (x^{8 y})

y = arcsin (2 x), x = \frac{3}{4}

y^{^{'}} = (y + 5) (x + 2)

\int_{0}^{1} \frac{18}{4 y - 1} d y

What is the tangent of f(x)=(x^2-1)/(x^2+x+1),(1,0) ?
The tangent of f(x)=(x^2-1)/(x^2+x+1),(1,0) is y= 2/3 x-2/3