What is the derivative of 1+3sin^3(x) ?

The derivative of 1+3sin^3(x) is 9sin^2(x)cos(x)

What is the first derivative of 1+3sin^3(x) ?

The first derivative of 1+3sin^3(x) is 9sin^2(x)cos(x)

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\frac{d}{d x} (1 + 3 sin^{3} (x))

9 sin^{2} (x) cos (x)

Solution steps

\frac{d}{d x} (1 + 3 sin^{3} (x))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (1) + \frac{d}{d x} (3 sin^{3} (x))

\frac{d}{d x} (1) = 0

\frac{d}{d x} (3 sin^{3} (x)) = 9 sin^{2} (x) cos (x)

= 0 + 9 sin^{2} (x) cos (x)

Simplify

= 9 sin^{2} (x) cos (x)

x^{2} + 1 + x^{2}

\int_{\frac{π}{4}}^{x} sec^{2} (t) d t

\int \frac{x + 1}{x ^{2} - 2 x - 1} d x

\int (2 t - 1)^{2} d t

\frac{d}{d x} (1 0^{t a n (π x)})

What is the derivative of 1+3sin^3(x) ?
The derivative of 1+3sin^3(x) is 9sin^2(x)cos(x)
What is the first derivative of 1+3sin^3(x) ?
The first derivative of 1+3sin^3(x) is 9sin^2(x)cos(x)