What is the derivative of (x^2+1)/(x+4) ?

The derivative of (x^2+1)/(x+4) is (x^2+8x-1)/((x+4)^2)

What is the first derivative of (x^2+1)/(x+4) ?

The first derivative of (x^2+1)/(x+4) is (x^2+8x-1)/((x+4)^2)

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derivative of

\frac{x ^{2} + 1}{x + 4}

\frac{x ^{2} + 8 x - 1}{( x + 4 ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{x ^{2} + 1}{x + 4})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{d}{d x} ( x ^{2} + 1 ) ( x + 4 ) - \frac{d}{d x} ( x + 4 ) ( x ^{2} + 1 )}{( x + 4 ) ^{2}}

\frac{d}{d x} (x^{2} + 1) = 2 x

\frac{d}{d x} (x + 4) = 1

= \frac{2 x ( x + 4 ) - 1 \cdot ( x ^{2} + 1 )}{( x + 4 ) ^{2}}

Simplify

\frac{2 x ( x + 4 ) - 1 \cdot ( x ^{2} + 1 )}{( x + 4 ) ^{2}} : \frac{x ^{2} + 8 x - 1}{( x + 4 ) ^{2}}

= \frac{x ^{2} + 8 x - 1}{( x + 4 ) ^{2}}

\frac{1}{6 s}

\int \frac{1}{θ ^{2}} cos (\frac{1}{θ}) d θ

\frac{\partial}{\partial x} (e^{s i n (2 x)})

\frac{d}{d x} (e^{t a n h (x)})

1 + x

What is the derivative of (x^2+1)/(x+4) ?
The derivative of (x^2+1)/(x+4) is (x^2+8x-1)/((x+4)^2)
What is the first derivative of (x^2+1)/(x+4) ?
The first derivative of (x^2+1)/(x+4) is (x^2+8x-1)/((x+4)^2)