What is the integral of 4xln(3x) ?

The integral of 4xln(3x) is 2x^2ln(3x)-x^2+C

Popular >

integral of 4xln(3x)

\int 4 x ln (3 x) d x

2 x^{2} ln (3 x) - x^{2} + C

Solution steps

\int 4 x ln (3 x) d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 4 \cdot \int x ln (3 x) d x

Apply Integration By Parts

: \frac{1}{2} x^{2} ln (3 x) - \int \frac{x}{2} d x

= 4 (\frac{1}{2} x^{2} ln (3 x) - \int \frac{x}{2} d x)

\int \frac{x}{2} d x = \frac{x ^{2}}{4}

= 4 (\frac{1}{2} x^{2} ln (3 x) - \frac{x ^{2}}{4})

Simplify

4 (\frac{1}{2} x^{2} ln (3 x) - \frac{x ^{2}}{4}) : 2 x^{2} ln (3 x) - x^{2}

= 2 x^{2} ln (3 x) - x^{2}

Add a constant to the solution

= 2 x^{2} ln (3 x) - x^{2} + C

(\frac{d y}{d x}) - (\frac{y}{3 x}) + (\frac{x}{3 y}) = 0

\int y e^{t y}

\frac{\partial}{\partial x} (\frac{3 x}{( x + y ) ^{3}})

f (x) = - 2 sin (x), at x = \frac{3 π}{4}

\int \frac{x ^{5}}{u} d x