What is the tangent of f(x)=-2sin(x),\at x=(3pi)/4 ?

The tangent of f(x)=-2sin(x),\at x=(3pi)/4 is y=sqrt(2)x-sqrt(2)-(3pi)/(2sqrt(2))

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tangent of f(x)=-2sin(x),\at x=(3pi)/4

tangent of

f (x) = - 2 sin (x), at x = \frac{3 π}{4}

y = 2 x - 2 - \frac{3 π}{2 2}

Solution steps

Find the tangent point:

(\frac{3 π}{4}, - 2)

Find the slope of

f (x) = - 2 sin (x) : \frac{df ( x )}{d x} = - 2 cos (x)

Compute the slope of

f (x) = - 2 sin (x)

x = \frac{3 π}{4} : m = 2

Find the line with slope m=

2

and passing through

(\frac{3 π}{4}, - 2) : y = 2 x - 2 - \frac{3 π}{2 2}

y = 2 x - 2 - \frac{3 π}{2 2}

\int \frac{x ^{5}}{u} d x

x \to 0 lim (sin (0))

\frac{\partial}{\partial x} (200 (y - x^{2}))

x \to - 2 lim (\frac{x - 1}{x ^{2} - 4})

\int \frac{2 x}{x ^{3}} d x

What is the tangent of f(x)=-2sin(x),\at x=(3pi)/4 ?
The tangent of f(x)=-2sin(x),\at x=(3pi)/4 is y=sqrt(2)x-sqrt(2)-(3pi)/(2sqrt(2))