What is the derivative of 1+e^{2x} ?

The derivative of 1+e^{2x} is 2e^{2x}

What is the first derivative of 1+e^{2x} ?

The first derivative of 1+e^{2x} is 2e^{2x}

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derivative of

1 + e^{2 x}

2 e^{2 x}

Solution steps

\frac{d}{d x} (1 + e^{2 x})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (1) + \frac{d}{d x} (e^{2 x})

\frac{d}{d x} (1) = 0

\frac{d}{d x} (e^{2 x}) = e^{2 x} \cdot 2

= 0 + e^{2 x} \cdot 2

Simplify

= 2 e^{2 x}

x \to 0 + lim (\frac{x ^{2}}{7} - \frac{7}{x})

x \to 0 lim (\frac{9 ^{x} - 1 5 ^{x}}{x})

\frac{d}{d x} (\frac{sin ( x )}{2 - cos ( x )})

\int (\frac{x - 1}{x ^{2}}) d x

y^{^{''}} - 8 y^{^{'}} + 17 = 0

What is the derivative of 1+e^{2x} ?
The derivative of 1+e^{2x} is 2e^{2x}
What is the first derivative of 1+e^{2x} ?
The first derivative of 1+e^{2x} is 2e^{2x}