What is (\partial)/(\partial x)(y*sin(x+y)) ?

The answer to (\partial)/(\partial x)(y*sin(x+y)) is ycos(x+y)

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(\partial)/(\partial x)(y*sin(x+y))

\frac{\partial}{\partial x} (y \cdot sin (x + y))

y cos (x + y)

Solution steps

\frac{\partial}{\partial x} (y sin (x + y))

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= y \frac{\partial}{\partial x} (sin (x + y))

Apply the chain rule:

cos (x + y) \frac{\partial}{\partial x} (x + y)

= cos (x + y) \frac{\partial}{\partial x} (x + y)

\frac{\partial}{\partial x} (x + y) = 1

= y cos (x + y) \cdot 1

Simplify

= y cos (x + y)

\int \frac{2}{2 x - x ^{2}} d x

g (x) = 4 - x

\frac{A}{y ^{13}} + B e^{y}

x = - 2, x = 1, y = 2 x^{2} + 11, y = 0

\int 16 sin^{2} (x) cos^{2} (x) d x

What is (\partial)/(\partial x)(y*sin(x+y)) ?
The answer to (\partial)/(\partial x)(y*sin(x+y)) is ycos(x+y)