What is the derivative of 3e^x+(x^2/(\sqrt[3]{x)}) ?

The derivative of 3e^x+(x^2/(\sqrt[3]{x)}) is 3e^x+(5x^{2/3})/3

What is the first derivative of 3e^x+(x^2/(\sqrt[3]{x)}) ?

The first derivative of 3e^x+(x^2/(\sqrt[3]{x)}) is 3e^x+(5x^{2/3})/3

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3 e^{x} + \frac{5 x ^{\frac{2}{3}}}{3}

Solution steps

Simplify

= \frac{d}{d x} (3 e^{x} + x^{\frac{5}{3}})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (3 e^{x}) + \frac{d}{d x} (x^{\frac{5}{3}})

\frac{d}{d x} (3 e^{x}) = 3 e^{x}

\frac{d}{d x} (x^{\frac{5}{3}}) = \frac{5 x ^{\frac{2}{3}}}{3}

= 3 e^{x} + \frac{5 x ^{\frac{2}{3}}}{3}

\int \frac{2 x ^{4} + 8 x ^{3} - x}{x ^{3}} d x

n = 2 \sum \infty ln (\frac{n}{n + 1})

f (x) = e^{x} + x^{e}

\frac{d}{d x} ((x + 1) (x - 2))

y (x + 9) + y^{^{'}} = 0, y (- 18) = 1

What is the derivative of 3e^x+(x^2/(\sqrt[3]{x)}) ?
The derivative of 3e^x+(x^2/(\sqrt[3]{x)}) is 3e^x+(5x^{2/3})/3
What is the first derivative of 3e^x+(x^2/(\sqrt[3]{x)}) ?
The first derivative of 3e^x+(x^2/(\sqrt[3]{x)}) is 3e^x+(5x^{2/3})/3