What is the derivative of f(x)=(4x^3+2x+5)/x ?

The derivative of f(x)=(4x^3+2x+5)/x is (8x^3-5)/(x^2)

What is the first derivative of f(x)=(4x^3+2x+5)/x ?

The first derivative of f(x)=(4x^3+2x+5)/x is (8x^3-5)/(x^2)

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derivative of

f (x) = \frac{4 x ^{3} + 2 x + 5}{x}

\frac{8 x ^{3} - 5}{x ^{2}}

Solution steps

\frac{d}{d x} (\frac{4 x ^{3} + 2 x + 5}{x})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{d}{d x} ( 4 x ^{3} + 2 x + 5 ) x - \frac{d x}{d x} ( 4 x ^{3} + 2 x + 5 )}{x ^{2}}

\frac{d}{d x} (4 x^{3} + 2 x + 5) = 12 x^{2} + 2

\frac{d x}{d x} = 1

= \frac{( 12 x ^{2} + 2 ) x - 1 \cdot ( 4 x ^{3} + 2 x + 5 )}{x ^{2}}

Simplify

\frac{( 12 x ^{2} + 2 ) x - 1 \cdot ( 4 x ^{3} + 2 x + 5 )}{x ^{2}} : \frac{8 x ^{3} - 5}{x ^{2}}

= \frac{8 x ^{3} - 5}{x ^{2}}

f (x) = \frac{5}{( x + 2 ) ^{2}}

\frac{d}{d x} (9 (x^{3} - x)^{4})

\int \frac{x}{( x ^{2} + a ^{2} ) ^{\frac{3}{2}}} d x

y^{^{''}} - 6 y^{^{'}} + 12 y = sin (2 x)

y^{^{''}} + y = e^{- x}

What is the derivative of f(x)=(4x^3+2x+5)/x ?
The derivative of f(x)=(4x^3+2x+5)/x is (8x^3-5)/(x^2)
What is the first derivative of f(x)=(4x^3+2x+5)/x ?
The first derivative of f(x)=(4x^3+2x+5)/x is (8x^3-5)/(x^2)