What is the derivative of f(x)= 5/((x+2)^2) ?

The derivative of f(x)= 5/((x+2)^2) is -(10)/((x+2)^3)

What is the first derivative of f(x)= 5/((x+2)^2) ?

The first derivative of f(x)= 5/((x+2)^2) is -(10)/((x+2)^3)

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derivative of

f (x) = \frac{5}{( x + 2 ) ^{2}}

- \frac{10}{( x + 2 ) ^{3}}

Solution steps

\frac{d}{d x} (\frac{5}{( x + 2 ) ^{2}})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 5 \frac{d}{d x} (\frac{1}{( x + 2 ) ^{2}})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= 5 \frac{d}{d x} ((x + 2)^{- 2})

Apply the chain rule:

- \frac{2}{( x + 2 ) ^{3}} \frac{d}{d x} (x + 2)

= - \frac{2}{( x + 2 ) ^{3}} \frac{d}{d x} (x + 2)

\frac{d}{d x} (x + 2) = 1

= 5 (- \frac{2}{( x + 2 ) ^{3}} \cdot 1)

Simplify

5 (- \frac{2}{( x + 2 ) ^{3}} \cdot 1) : - \frac{10}{( x + 2 ) ^{3}}

= - \frac{10}{( x + 2 ) ^{3}}

\frac{d}{d x} (9 (x^{3} - x)^{4})

\int \frac{x}{( x ^{2} + a ^{2} ) ^{\frac{3}{2}}} d x

y^{^{''}} - 6 y^{^{'}} + 12 y = sin (2 x)

y^{^{''}} + y = e^{- x}

y = x (49.7)

What is the derivative of f(x)= 5/((x+2)^2) ?
The derivative of f(x)= 5/((x+2)^2) is -(10)/((x+2)^3)
What is the first derivative of f(x)= 5/((x+2)^2) ?
The first derivative of f(x)= 5/((x+2)^2) is -(10)/((x+2)^3)