What is the derivative of 0.04t^3-0.12t^2 ?

The derivative of 0.04t^3-0.12t^2 is 0.12t^2-0.24t

What is the first derivative of 0.04t^3-0.12t^2 ?

The first derivative of 0.04t^3-0.12t^2 is 0.12t^2-0.24t

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derivative of

0.04 t^{3} - 0.12 t^{2}

0.12 t^{2} - 0.24 t

Solution steps

\frac{d}{d t} (0.04 t^{3} - 0.12 t^{2})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d t} (0.04 t^{3}) - \frac{d}{d t} (0.12 t^{2})

\frac{d}{d t} (0.04 t^{3}) = 0.12 t^{2}

\frac{d}{d t} (0.12 t^{2}) = 0.24 t

= 0.12 t^{2} - 0.24 t

x \to 3 - lim (\frac{x + 2}{x ^{2} - 9})

x + 8

\frac{\partial}{\partial x} (e^{\frac{x}{y}})

\frac{\partial}{\partial r} (r sin (t) sin (x))

\int_{0}^{1} \frac{17}{4 y - 1} d y

What is the derivative of 0.04t^3-0.12t^2 ?
The derivative of 0.04t^3-0.12t^2 is 0.12t^2-0.24t
What is the first derivative of 0.04t^3-0.12t^2 ?
The first derivative of 0.04t^3-0.12t^2 is 0.12t^2-0.24t