What is the derivative of e^x+2e^{-x} ?

The derivative of e^x+2e^{-x} is e^x-2e^{-x}

What is the first derivative of e^x+2e^{-x} ?

The first derivative of e^x+2e^{-x} is e^x-2e^{-x}

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\frac{d}{d x} (e^{x} + 2 e^{- x})

e^{x} - 2 e^{- x}

Solution steps

\frac{d}{d x} (e^{x} + 2 e^{- x})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (e^{x}) + \frac{d}{d x} (2 e^{- x})

\frac{d}{d x} (e^{x}) = e^{x}

\frac{d}{d x} (2 e^{- x}) = - 2 e^{- x}

= e^{x} - 2 e^{- x}

sin (x), cos (x), [0, 2 π]

(x^{2} + y) + (x + e^{y}) \frac{d y}{d x} = 0

\int \frac{3 y ^{2} + 1}{y ^{3} + y} d y

\int sin^{3} (x) d x

What is the derivative of e^x+2e^{-x} ?
The derivative of e^x+2e^{-x} is e^x-2e^{-x}
What is the first derivative of e^x+2e^{-x} ?
The first derivative of e^x+2e^{-x} is e^x-2e^{-x}