What is the derivative of y= 4/((3x)^3)+2cos(x) ?

The derivative of y= 4/((3x)^3)+2cos(x) is -4/(9x^4)-2sin(x)

What is the first derivative of y= 4/((3x)^3)+2cos(x) ?

The first derivative of y= 4/((3x)^3)+2cos(x) is -4/(9x^4)-2sin(x)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

derivative of

y = \frac{4}{( 3 x ) ^{3}} + 2 cos (x)

- \frac{4}{9 x ^{4}} - 2 sin (x)

Solution steps

\frac{d}{d x} (\frac{4}{( 3 x ) ^{3}} + 2 cos (x))

Simplify

\frac{4}{( 3 x ) ^{3}} + 2 cos (x) : \frac{4}{27 x ^{3}} + 2 cos (x)

= \frac{d}{d x} (\frac{4}{27 x ^{3}} + 2 cos (x))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (\frac{4}{27 x ^{3}}) + \frac{d}{d x} (2 cos (x))

\frac{d}{d x} (\frac{4}{27 x ^{3}}) = - \frac{4}{9 x ^{4}}

\frac{d}{d x} (2 cos (x)) = - 2 sin (x)

= - \frac{4}{9 x ^{4}} - 2 sin (x)

\int \frac{2 x - 3}{x ^{3} + 10 x} d x

\frac{d}{d x} ((\frac{x - 7}{x + 4})^{10})

\int sin (\frac{1}{6}) x sin (\frac{1}{12}) x d x

x \to 0 lim (\frac{3 e ^{x}}{x + 1})

y^{^{'}} = x^{2} + 4

What is the derivative of y= 4/((3x)^3)+2cos(x) ?
The derivative of y= 4/((3x)^3)+2cos(x) is -4/(9x^4)-2sin(x)
What is the first derivative of y= 4/((3x)^3)+2cos(x) ?
The first derivative of y= 4/((3x)^3)+2cos(x) is -4/(9x^4)-2sin(x)