What is area sin(2x),cos(x),[ pi/6 , pi/2 ] ?

The answer to area sin(2x),cos(x),[ pi/6 , pi/2 ] is 1/4

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area sin(2x),cos(x),[ pi/6 , pi/2 ]

area

sin (2 x), cos (x), [\frac{π}{6}, \frac{π}{2}]

\frac{1}{4}

Decimal Notation

0.25

Solution steps

Apply the area formula:

\int_{\frac{π}{6}}^{\frac{π}{2}} ∣ sin (2 x) - cos (x) ∣ d x

Solve

\int_{\frac{π}{6}}^{\frac{π}{2}} ∣ sin (2 x) - cos (x) ∣ d x : \frac{1}{4}

The area is:

= \frac{1}{4}

y = - ln (x)

x \to 0 lim (\frac{sin ( 8 x )}{sin ( 7 x )})

\frac{d}{d x} (x^{2} + y)

\frac{\partial}{\partial x} (arccos (\frac{y}{x}))

y^{^{'}} x^{2} - 18 = 4 x

What is area sin(2x),cos(x),[ pi/6 , pi/2 ] ?
The answer to area sin(2x),cos(x),[ pi/6 , pi/2 ] is 1/4