What is (\partial)/(\partial x)(3y^2+20x^2y^3) ?

The answer to (\partial)/(\partial x)(3y^2+20x^2y^3) is 40y^3x

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(\partial)/(\partial x)(3y^2+20x^2y^3)

\frac{\partial}{\partial x} (3 y^{2} + 20 x^{2} y^{3})

40 y^{3} x

Solution steps

\frac{\partial}{\partial x} (3 y^{2} + 20 x^{2} y^{3})

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (3 y^{2}) + \frac{\partial}{\partial x} (20 x^{2} y^{3})

\frac{\partial}{\partial x} (3 y^{2}) = 0

\frac{\partial}{\partial x} (20 x^{2} y^{3}) = 40 y^{3} x

= 0 + 40 y^{3} x

Simplify

= 40 y^{3} x

cos^{2} (π t)

x^{2} y^{^{'}} + x y = y^{2}

x \to - 1 lim ((x + 1) \cdot ln (x + 1))

\frac{2}{s + 1} + 32 \cdot \frac{s}{s ^{2} + 9}

f (x) = x^{4}, (- 1, 1)

What is (\partial)/(\partial x)(3y^2+20x^2y^3) ?
The answer to (\partial)/(\partial x)(3y^2+20x^2y^3) is 40y^3x