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Popular >

x^2y^'+xy=y^2

Solution

x^{2} y^{^{'}} + x y = y^{2}

Solution

y = \frac{2 x}{1 + 2 c _{1} x ^{2}}

Solution steps

x^{2} y^{'} (x) + x y = y^{2}

Solve Bernoulli ODE:

y = \frac{2 x}{1 + 2 c _{1} x ^{2}}

y = \frac{2 x}{1 + 2 c _{1} x ^{2}}

Popular Examples

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x \to - 1 lim ((x + 1) \cdot ln (x + 1))

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\frac{2}{s + 1} + 32 \cdot \frac{s}{s ^{2} + 9}

tangent of f(x)=x^4,(-1,1)tangent of

f (x) = x^{4}, (- 1, 1)

slope of y=4x-2x^2 slope

y = 4 x - 2 x^{2}

derivative of (ax+b^n)

\frac{d}{d x} ((a x + b)^{n})

Frequently Asked Questions (FAQ)

What is the solution for x^2y^'+xy=y^2 ?
The solution for x^2y^'+xy=y^2 is y=(2x)/(1+2c_{1)x^2}