What is the integral from 0 to r of xsqrt(r^2-x^2) ?

The integral from 0 to r of xsqrt(r^2-x^2) is ((r^2)^{3/2})/3

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integral from 0 to r of xsqrt(r^2-x^2)

\int_{0}^{r} x r^{2} - x^{2} d x

\frac{( r ^{2} ) ^{\frac{3}{2}}}{3}

Solution steps

\int_{0}^{r} x r^{2} - x^{2} d x

Apply u-substitution

: \int_{r^{2}}^{0} - \frac{u}{2} d u

= \int_{r^{2}}^{0} - \frac{u}{2} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - \frac{1}{2} \cdot \int_{r^{2}}^{0} u d u

Apply the Power Rule

: [\frac{2}{3} u^{\frac{3}{2}}]_{r^{2}}^{0}

= - \frac{1}{2} [\frac{2}{3} u^{\frac{3}{2}}]_{r^{2}}^{0}

Compute the boundaries:

- \frac{2}{3} (r^{2})^{\frac{3}{2}}

= - \frac{1}{2} (- \frac{2}{3} (r^{2})^{\frac{3}{2}})

Simplify

= \frac{( r ^{2} ) ^{\frac{3}{2}}}{3}

\int \frac{x}{( x ^{2} - 4 ) ( x + 3 )} d x

y = 1 - e^{x}

\int 1 5^{x} d x

\frac{d}{d x} ((1 + 2 x)^{2})

\frac{1}{x ^{2}}

What is the integral from 0 to r of xsqrt(r^2-x^2) ?
The integral from 0 to r of xsqrt(r^2-x^2) is ((r^2)^{3/2})/3