What is the derivative of y=1-e^x ?

The derivative of y=1-e^x is -e^x

What is the first derivative of y=1-e^x ?

The first derivative of y=1-e^x is -e^x

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derivative of

y = 1 - e^{x}

- e^{x}

Solution steps

\frac{d}{d x} (1 - e^{x})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (1) - \frac{d}{d x} (e^{x})

\frac{d}{d x} (1) = 0

\frac{d}{d x} (e^{x}) = e^{x}

= 0 - e^{x}

Simplify

= - e^{x}

\int 1 5^{x} d x

\frac{d}{d x} ((1 + 2 x)^{2})

\frac{1}{x ^{2}}

\int \frac{x + 1}{x ^{2} + 1} d x

f (x) = \frac{5}{2 5 x + 6}, at x = 2

What is the derivative of y=1-e^x ?
The derivative of y=1-e^x is -e^x
What is the first derivative of y=1-e^x ?
The first derivative of y=1-e^x is -e^x