What is the integral of e^{1.25x}-4x ?

The integral of e^{1.25x}-4x is 0.8e^{1.25x}-2x^2+C

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integral of e^{1.25x}-4x

\int e^{1.25 x} - 4 x d x

0.8 e^{1.25 x} - 2 x^{2} + C

Solution steps

\int e^{1.25 x} - 4 x d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int e^{1.25 x} d x - \int 4 x d x

\int e^{1.25 x} d x = 0.8 e^{1.25 x}

\int 4 x d x = 2 x^{2}

= 0.8 e^{1.25 x} - 2 x^{2}

Add a constant to the solution

= 0.8 e^{1.25 x} - 2 x^{2} + C

\frac{\partial}{\partial x} (6 x^{\frac{1}{3}} y^{\frac{1}{2}})

\int \frac{e ^{x}}{1 + 25 e ^{2 x}} d x

f (x) = 2 x + \frac{3}{x}, at x = - 1

\frac{\partial}{\partial x} (\frac{arctan ( \cdot y ^{2} )}{x})

\frac{d y}{d t} + e^{t} y = - e^{t}

What is the integral of e^{1.25x}-4x ?
The integral of e^{1.25x}-4x is 0.8e^{1.25x}-2x^2+C