What is the limit as x approaches 0+of 6-ln(x) ?

The limit as x approaches 0+of 6-ln(x) is infinity

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limit as x approaches 0+of 6-ln(x)

x \to 0 + lim (6 - ln (x))

\infty

Solution steps

x \to 0 + lim (6 - ln (x))

x \to a lim [f (x) \pm g (x)] = x \to a lim f (x) \pm x \to a lim g (x)

With the exception of indeterminate form

= x \to 0 + lim (6) - x \to 0 + lim (ln (x))

x \to 0 + lim (6) = 6

x \to 0 + lim (ln (x)) = - \infty

= 6 - (- \infty)

Simplify

6 - (- \infty) : \infty

= \infty

n = 3 \sum \infty \frac{1}{n + 2}

y^{^{'}} (x) = \frac{3 x ^{2}}{3 y ^{2} - 7}, y (1) = 0

f (x) = 3 x + 4, (7, 5)

\frac{\partial}{\partial x} (0.1 \cdot y^{2} + 0.05 \cdot x \cdot y)

\int (sec (x)) d x

What is the limit as x approaches 0+of 6-ln(x) ?
The limit as x approaches 0+of 6-ln(x) is infinity