What is the sum from n=4 to infinity of 1/(sqrt(n)) ?

The sum from n=4 to infinity of 1/(sqrt(n)) is diverges

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sum from n=4 to infinity of 1/(sqrt(n))

n = 4 \sum \infty \frac{1}{n}

diverges

Solution steps

n = 4 \sum \infty \frac{1}{n}

Apply p-Series Test:

diverges

= diverges

\int 8 x^{3} (2 x^{4} + 4)^{4} d x

1 + (\frac{2}{5})^{\circ} x (\frac{2}{3})^{\circ} - 25

g (x) = [ln (5 x - 2)]^{4}

\frac{1}{12 x ^{3}}

\int_{0}^{\infty} \frac{4}{x ^{2} + 4} d x

What is the sum from n=4 to infinity of 1/(sqrt(n)) ?
The sum from n=4 to infinity of 1/(sqrt(n)) is diverges