What is (\partial)/(\partial y)(x^7+2^y+x^y) ?

The answer to (\partial)/(\partial y)(x^7+2^y+x^y) is x^yln(x)+ln(2)*2^y

Popular >

(\partial)/(\partial y)(x^7+2^y+x^y)

\frac{\partial}{\partial y} (x^{7} + 2^{y} + x^{y})

x^{y} ln (x) + ln (2) \cdot 2^{y}

Solution steps

\frac{\partial}{\partial y} (x^{7} + 2^{y} + x^{y})

Treat

x

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial y} (x^{7}) + \frac{\partial}{\partial y} (2^{y}) + \frac{\partial}{\partial y} (x^{y})

\frac{\partial}{\partial y} (x^{7}) = 0

\frac{\partial}{\partial y} (2^{y}) = 2^{y} ln (2)

\frac{\partial}{\partial y} (x^{y}) = x^{y} ln (x)

= 0 + 2^{y} ln (2) + x^{y} ln (x)

Simplify

= x^{y} ln (x) + ln (2) \cdot 2^{y}

f (x) = 2 θ - 2 sin (θ)

f (x) = \frac{6}{x}, at x = - 2

(7 x + 1)^{2}

x^{2} + 2 x, 2 x + 1

\frac{d}{d x} (25)

What is (\partial)/(\partial y)(x^7+2^y+x^y) ?
The answer to (\partial)/(\partial y)(x^7+2^y+x^y) is x^yln(x)+ln(2)*2^y