What is the derivative of 3x^3-2x^2 ?

The derivative of 3x^3-2x^2 is 9x^2-4x

What is the first derivative of 3x^3-2x^2 ?

The first derivative of 3x^3-2x^2 is 9x^2-4x

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\frac{d}{d x} (3 x^{3} - 2 x^{2})

9 x^{2} - 4 x

Solution steps

\frac{d}{d x} (3 x^{3} - 2 x^{2})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (3 x^{3}) - \frac{d}{d x} (2 x^{2})

\frac{d}{d x} (3 x^{3}) = 9 x^{2}

\frac{d}{d x} (2 x^{2}) = 4 x

= 9 x^{2} - 4 x

f (x) = (4 x + 3)^{2}

x \to 0 lim (tan^{x} (x))

2 x - 4

\int_{- 8}^{0} \frac{y}{8} + y + 9 d y

\int (n + 3)^{3} d n

What is the derivative of 3x^3-2x^2 ?
The derivative of 3x^3-2x^2 is 9x^2-4x
What is the first derivative of 3x^3-2x^2 ?
The first derivative of 3x^3-2x^2 is 9x^2-4x