What is the derivative of f(x)=(8x-x^2)^3 ?

The derivative of f(x)=(8x-x^2)^3 is 3(8x-x^2)^2(8-2x)

What is the first derivative of f(x)=(8x-x^2)^3 ?

The first derivative of f(x)=(8x-x^2)^3 is 3(8x-x^2)^2(8-2x)

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derivative of

f (x) = (8 x - x^{2})^{3}

3 (8 x - x^{2})^{2} (8 - 2 x)

Solution steps

\frac{d}{d x} ((8 x - x^{2})^{3})

Apply the chain rule:

3 (8 x - x^{2})^{2} \frac{d}{d x} (8 x - x^{2})

= 3 (8 x - x^{2})^{2} \frac{d}{d x} (8 x - x^{2})

\frac{d}{d x} (8 x - x^{2}) = 8 - 2 x

= 3 (8 x - x^{2})^{2} (8 - 2 x)

\int sin (5 x) d x

x \to - 1 lim (x^{3 - 4 x^{2} + 1})

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\frac{\partial}{\partial x} (z sin^{2} (x))

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What is the derivative of f(x)=(8x-x^2)^3 ?
The derivative of f(x)=(8x-x^2)^3 is 3(8x-x^2)^2(8-2x)
What is the first derivative of f(x)=(8x-x^2)^3 ?
The first derivative of f(x)=(8x-x^2)^3 is 3(8x-x^2)^2(8-2x)