What is the tangent of f(x)=6x^2+2x-7,\at x=-4 ?

The tangent of f(x)=6x^2+2x-7,\at x=-4 is y=-46x-103

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tangent of f(x)=6x^2+2x-7,\at x=-4

tangent of

f (x) = 6 x^{2} + 2 x - 7, at x = - 4

y = - 46 x - 103

Solution steps

Find the tangent point:

(- 4, 81)

Find the slope of

f (x) = 6 x^{2} + 2 x - 7 : \frac{df ( x )}{d x} = 12 x + 2

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = - 46

Find the line with slope m=

- 46

and passing through

(- 4, 81) : y = - 46 x - 103

y = - 46 x - 103

(1 + e^{x^{2}})^{3}

\frac{\partial}{\partial z} (x + \frac{y}{z})

n = 0 \sum \infty \frac{1}{n + 4}

\int x (x^{2} + 1)^{10} d x

y = 6 - x^{2}, y = x

What is the tangent of f(x)=6x^2+2x-7,\at x=-4 ?
The tangent of f(x)=6x^2+2x-7,\at x=-4 is y=-46x-103