What is the integral from 1 to 5 of 3x^2+1/(12x^2) ?

The integral from 1 to 5 of 3x^2+1/(12x^2) is 1861/15

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integral from 1 to 5 of 3x^2+1/(12x^2)

\int_{1}^{5} 3 x^{2} + \frac{1}{12 x ^{2}} d x

\frac{1861}{15}

Decimal

124.06666 \dots

Solution steps

\int_{1}^{5} 3 x^{2} + \frac{1}{12 x ^{2}} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{1}^{5} 3 x^{2} d x + \int_{1}^{5} \frac{1}{12 x ^{2}} d x

\int_{1}^{5} 3 x^{2} d x = 124

\int_{1}^{5} \frac{1}{12 x ^{2}} d x = \frac{1}{15}

= 124 + \frac{1}{15}

Simplify

124 + \frac{1}{15} : \frac{1861}{15}

= \frac{1861}{15}

t = y + y^{^{'}}

\int 5 - x^{2} d x

\int_{- 3}^{3} (2 x^{4} - 3 x^{3}) d x

\int x e x d x

sin (sin (sin (x)))

What is the integral from 1 to 5 of 3x^2+1/(12x^2) ?
The integral from 1 to 5 of 3x^2+1/(12x^2) is 1861/15