What is the solution for (dy)/(dx)=((2x(y-1))/(x^2+3)) ?

The solution for (dy)/(dx)=((2x(y-1))/(x^2+3)) is y=e^{c_{1}}x^2+3e^{c_{1}}+1

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(dy)/(dx)=((2x(y-1))/(x^2+3))

\frac{d y}{d x} = (\frac{2 x ( y - 1 )}{x ^{2} + 3})

y = e^{c_{1}} x^{2} + 3 e^{c_{1}} + 1

Solution steps

\frac{d y}{d x} = (\frac{2 x ( y - 1 )}{x ^{2} + 3})

Solve separable ODE:

y = e^{c_{1}} x^{2} + 3 e^{c_{1}} + 1

y = e^{c_{1}} x^{2} + 3 e^{c_{1}} + 1

f (x) = e^{x}, at x = 0.3

32 x

t^{2} cos (k t)

\int_{1}^{2} (3 x^{2} + 2 x + 1) d x

\frac{\partial}{\partial y} ((x y)^{\frac{1}{3}})

What is the solution for (dy)/(dx)=((2x(y-1))/(x^2+3)) ?
The solution for (dy)/(dx)=((2x(y-1))/(x^2+3)) is y=e^{c_{1}}x^2+3e^{c_{1}}+1