What is area y=x^2,y=2x+6 ?

The answer to area y=x^2,y=2x+6 is -(20sqrt(7))/3+16sqrt(7)

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area y=x^2,y=2x+6

area

y = x^{2}, y = 2 x + 6

- \frac{20 7}{3} + 167

Decimal Notation

24.69367 \dots

Solution steps

Apply the area formula:

\int_{1 - 7}^{1 + 7} x^{2} - (2 x + 6) d x

Solve

\int_{1 - 7}^{1 + 7} x^{2} - (2 x + 6) d x : - \frac{20 7}{3} + 167

The area is:

= - \frac{20 7}{3} + 167

sin (2 x) d x + cos (8 y) d y = 0, y (\frac{π}{2}) = \frac{π}{8}

2 cos (3 t)

\int_{1}^{2} x^{4} + \frac{1}{4 x ^{4}} d x

\int_{0}^{5} x 25 - x^{2} d x

15 cos (3 t)

What is area y=x^2,y=2x+6 ?
The answer to area y=x^2,y=2x+6 is -(20sqrt(7))/3+16sqrt(7)