What is the limit as x approaches 0 of 1/x-1/(x^2+1) ?

The limit as x approaches 0 of 1/x-1/(x^2+1) is diverges

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

limit as x approaches 0 of 1/x-1/(x^2+1)

x \to 0 lim (\frac{1}{x} - \frac{1}{x ^{2} + 1})

diverges

Solution steps

x \to 0 lim (\frac{1}{x} - \frac{1}{x ^{2} + 1})

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to 0 + lim (\frac{1}{x} - \frac{1}{x ^{2} + 1}) = \infty

x \to 0 - lim (\frac{1}{x} - \frac{1}{x ^{2} + 1}) = - \infty

= diverges

\int \frac{1}{1 - 25 x ^{2}} d x

f (x) = \frac{x ^{3} + x ^{2} + 6}{x}, at x = 1

\frac{\partial}{\partial x} (3 x^{4} y^{8} + 7 x^{5} y^{6})

\int 7 (1 + tan^{2} (a)) d a

h (x) = \frac{8}{x} - \frac{2}{x ^{3}} + \frac{1}{x ^{4}}

What is the limit as x approaches 0 of 1/x-1/(x^2+1) ?
The limit as x approaches 0 of 1/x-1/(x^2+1) is diverges