What is the derivative of f(x)=7e^{(3x^2-2x+7)} ?

The derivative of f(x)=7e^{(3x^2-2x+7)} is 7e^{3x^2-2x+7}(6x-2)

What is the first derivative of f(x)=7e^{(3x^2-2x+7)} ?

The first derivative of f(x)=7e^{(3x^2-2x+7)} is 7e^{3x^2-2x+7}(6x-2)

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derivative of

f (x) = 7 e^{(3 x^{2} - 2 x + 7)}

7 e^{3 x^{2} - 2 x + 7} (6 x - 2)

Solution steps

\frac{d}{d x} (7 e^{3 x^{2} - 2 x + 7})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 7 \frac{d}{d x} (e^{3 x^{2} - 2 x + 7})

Apply the chain rule:

e^{3 x^{2} - 2 x + 7} \frac{d}{d x} (3 x^{2} - 2 x + 7)

= e^{3 x^{2} - 2 x + 7} \frac{d}{d x} (3 x^{2} - 2 x + 7)

\frac{d}{d x} (3 x^{2} - 2 x + 7) = 6 x - 2

= 7 e^{3 x^{2} - 2 x + 7} (6 x - 2)

y^{^{'}} = \frac{1}{sec ^{2} ( x )}

\frac{d}{d x} (x^{2} + y^{2} + z^{2})

y = cos (x), y = 2 - cos (x), 0 \leq x \leq 2 π

\frac{d}{d y} (5 x + 4 y)

\int_{- 1}^{4} (2 x + 4)^{2} d x

What is the derivative of f(x)=7e^{(3x^2-2x+7)} ?
The derivative of f(x)=7e^{(3x^2-2x+7)} is 7e^{3x^2-2x+7}(6x-2)
What is the first derivative of f(x)=7e^{(3x^2-2x+7)} ?
The first derivative of f(x)=7e^{(3x^2-2x+7)} is 7e^{3x^2-2x+7}(6x-2)