What is the solution for (x^2+xy-y^2)dx+(xy)dy=0 ?

The solution for (x^2+xy-y^2)dx+(xy)dy=0 is y=-\W(x/(c_{1)})x-x

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(x^2+xy-y^2)dx+(xy)dy=0

(x^{2} + x y - y^{2}) d x + (x y) d y = 0

y = - W (\frac{x}{c _{1}}) x - x

Solution steps

(x^{2} + x y - y^{2}) d x + (x y) d y = 0

Solve using substitution:

y = - W (\frac{x}{c _{1}}) x - x

y = - W (\frac{x}{c _{1}}) x - x

ln (x + 2), 3

x \to 0 lim (x \cdot ln (x^{2}))

\frac{d}{d t} (e^{t a n (t)})

\frac{d ^{4}}{d x ^{4}} (e^{x^{2}})

12 x^{2} y + y^{^{'}} = - 2 x^{2}

What is the solution for (x^2+xy-y^2)dx+(xy)dy=0 ?
The solution for (x^2+xy-y^2)dx+(xy)dy=0 is y=-\W(x/(c_{1)})x-x