What is the sum from n=1 to infinity of (n^2)/(n+1) ?

The sum from n=1 to infinity of (n^2)/(n+1) is diverges

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sum from n=1 to infinity of (n^2)/(n+1)

n = 1 \sum \infty \frac{n ^{2}}{n + 1}

diverges

Solution steps

n = 1 \sum \infty \frac{n ^{2}}{n + 1}

Apply Series Divergence Test:

diverges

= diverges

y = - \frac{x}{9 y}

\frac{d}{d t} (- 4 t^{2} + 176 t + 100)

\frac{d}{d x} (sec (x^{2} + 2))

\int_{\frac{π}{9}}^{\infty} \frac{2}{x} d x

n = 2 \sum \infty \frac{5}{7 ^{n}}

What is the sum from n=1 to infinity of (n^2)/(n+1) ?
The sum from n=1 to infinity of (n^2)/(n+1) is diverges