What is the derivative of 25x^8-34x^5+2^3-x ?

The derivative of 25x^8-34x^5+2^3-x is 200x^7-170x^4-1

What is the first derivative of 25x^8-34x^5+2^3-x ?

The first derivative of 25x^8-34x^5+2^3-x is 200x^7-170x^4-1

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derivative of

25 x^{8} - 34 x^{5} + 2^{3} - x

200 x^{7} - 170 x^{4} - 1

Solution steps

\frac{d}{d x} (25 x^{8} - 34 x^{5} + 2^{3} - x)

Simplify

25 x^{8} - 34 x^{5} + 2^{3} - x : 25 x^{8} - 34 x^{5} + 8 - x

= \frac{d}{d x} (25 x^{8} - 34 x^{5} + 8 - x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (25 x^{8}) - \frac{d}{d x} (34 x^{5}) + \frac{d}{d x} (8) - \frac{d x}{d x}

\frac{d}{d x} (25 x^{8}) = 200 x^{7}

\frac{d}{d x} (34 x^{5}) = 170 x^{4}

\frac{d}{d x} (8) = 0

\frac{d x}{d x} = 1

= 200 x^{7} - 170 x^{4} + 0 - 1

Simplify

= 200 x^{7} - 170 x^{4} - 1

(e^{t} x + 1) d t + (e^{t} - 1) d x = 0

\int x (x + 4)^{2} d x

\int \frac{x ^{2}}{7 + x} d x

\int e^{s x} d x

\int x^{2} sec^{2} (x^{3}) d x

What is the derivative of 25x^8-34x^5+2^3-x ?
The derivative of 25x^8-34x^5+2^3-x is 200x^7-170x^4-1
What is the first derivative of 25x^8-34x^5+2^3-x ?
The first derivative of 25x^8-34x^5+2^3-x is 200x^7-170x^4-1