What is the integral of e^{sx} ?

The integral of e^{sx} is 1/s e^{sx}+C

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integral of e^{sx}

\int e^{s x} d x

\frac{1}{s} e^{s x} + C

Solution steps

\int e^{s x} d x

Apply u-substitution

: \int \frac{e ^{u}}{s} d u

= \int \frac{e ^{u}}{s} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{s} \cdot \int e^{u} d u

Use the common integral:

\int e^{u} d u = e^{u}

= \frac{1}{s} e^{u}

Substitute back

u = s x

= \frac{1}{s} e^{s x}

Add a constant to the solution

= \frac{1}{s} e^{s x} + C

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